created at May 1, 2021

Circle

Area:

A=\frac{\pi \cdot d^{2}}{4}

L=\pi \cdot d

I_{x}=I_{y}=\frac{\pi \cdot d^{4}}{64};\quad I_{\rho}=\frac{\pi \cdot d^{4}}{32};

W_{x}=W_{y}=\frac{\pi \cdot d^{3}}{32};\quad W_{\rho}=\frac{\pi \cdot d^{3}}{16};

i_{x} = i_{y} = \frac{d}{4}